The Outer Mizbeach

The Outer Mizbe’ach was 5 amos by 5 amos. [see “D”] (Shemos 27:1). In the center of the Mizbe’ach was The Ma’aracha (woodpile). The Ma’aracha was 1 amah (cubit) by 1 amah [see “E”] ( 62a) [see “B”].

Question: What is the space between the sides of the Ma’aracha and the sides of the Mizbe’ach [see “F”]?

Answer: (5-1) /2 = 2 amos

 

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